CIRC ,\]THEREFORE \[2A=90{}^\circ -2B\] \[\therefore \COS 2A=\sin 2B\].

"> CIRC ,\]THEREFORE \[2A=90{}^\circ -2B\] \[\therefore \COS 2A=\sin 2B\].

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If \[\tan A=\frac{1}{2},\tan B=\frac{1}{3},\]then \[\cos 2A=\] [CET 1989]

Joint Entrance Exam - Main (JEE Main) Mathematics in Joint Entrance Exam - Main (JEE Main) 11 months ago

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\[A+B=45{}^\CIRC ,\]THEREFORE \[2A=90{}^\circ -2B\] \[\therefore \COS 2A=\sin 2B\].

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Posted on 20 Aug 2024, this text provides information on Joint Entrance Exam - Main (JEE Main) related to Mathematics in Joint Entrance Exam - Main (JEE Main). Please note that while accuracy is prioritized, the data presented might not be entirely correct or up-to-date. This information is offered for general knowledge and informational purposes only, and should not be considered as a substitute for professional advice.

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