COS A=\frac{{{B}^{2}}+{{c}^{2}}-{{a}^{2}}}{2BC}\].

"> COS A=\frac{{{B}^{2}}+{{c}^{2}}-{{a}^{2}}}{2BC}\].

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In \[\Delta \,ABC\], \[a=2cm,b=3cm\] and \[c=4cm\] , then angle A is [MNR 1973; MP PET 1984, 2002]

Joint Entrance Exam - Main (JEE Main) Mathematics in Joint Entrance Exam - Main (JEE Main) 11 months ago

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Use \[\COS A=\frac{{{B}^{2}}+{{c}^{2}}-{{a}^{2}}}{2BC}\].

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Posted on 21 Aug 2024, this text provides information on Joint Entrance Exam - Main (JEE Main) related to Mathematics in Joint Entrance Exam - Main (JEE Main). Please note that while accuracy is prioritized, the data presented might not be entirely correct or up-to-date. This information is offered for general knowledge and informational purposes only, and should not be considered as a substitute for professional advice.

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