DELTA P=\frac{4T}{r}\ \Rightarrow \frac{\Delta {{P}_{1}}}{\Delta {{P}_{2}}}=4\]\[\therefore \ \frac{{{r}_{2}}}{{{r}_{1}}}=4\] and \[\frac{{{V}_{1}}}{{{V}_{2}}}={{\LEFT( \frac{{{r}_{1}}}{{{r}_{2}}} \right)}^{3}}=\frac{1}{64}\]

"> DELTA P=\frac{4T}{r}\ \Rightarrow \frac{\Delta {{P}_{1}}}{\Delta {{P}_{2}}}=4\]\[\therefore \ \frac{{{r}_{2}}}{{{r}_{1}}}=4\] and \[\frac{{{V}_{1}}}{{{V}_{2}}}={{\LEFT( \frac{{{r}_{1}}}{{{r}_{2}}} \right)}^{3}}=\frac{1}{64}\]

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Excess pressure of one soap bubble is four times more than the other. Then the ratio of volume of first bubble to another one is  [CPMT 1997; MH CET 2000]

Joint Entrance Exam - Main (JEE Main) Physics in Joint Entrance Exam - Main (JEE Main) 11 months ago

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\[\DELTA P=\frac{4T}{r}\ \Rightarrow \frac{\Delta {{P}_{1}}}{\Delta {{P}_{2}}}=4\]\[\therefore \ \frac{{{r}_{2}}}{{{r}_{1}}}=4\] and \[\frac{{{V}_{1}}}{{{V}_{2}}}={{\LEFT( \frac{{{r}_{1}}}{{{r}_{2}}} \right)}^{3}}=\frac{1}{64}\]

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Posted on 17 Aug 2024, this text provides information on Joint Entrance Exam - Main (JEE Main) related to Physics in Joint Entrance Exam - Main (JEE Main). Please note that while accuracy is prioritized, the data presented might not be entirely correct or up-to-date. This information is offered for general knowledge and informational purposes only, and should not be considered as a substitute for professional advice.

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