G}'=g-{{\omega }^{
2
}}R{{\cos }^{2}}\lambda \] For weightlessness at equator \[\lambda =
0
{}^\circ \] and \[g'=0\] \ \[0=g-{{\omega }^{2}}R\]Þ \[\omega =\sqrt{\frac{g}{R}}=\frac{1}{800}\frac{
RAD
}{\
SEC
}\]