LEFT( \frac{1}{2}M{{v}^{2}} \right)=J(m.C.\Delta \theta )\] Þ \[\frac{1}{4}\TIMES 1\times {{(50)}^{2}}=4.2[200\times 0.105\times \Delta \theta ]\]Þ \[\Delta \theta =7.1{}^\circ C\]

"> LEFT( \frac{1}{2}M{{v}^{2}} \right)=J(m.C.\Delta \theta )\] Þ \[\frac{1}{4}\TIMES 1\times {{(50)}^{2}}=4.2[200\times 0.105\times \Delta \theta ]\]Þ \[\Delta \theta =7.1{}^\circ C\]

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A hammer of mass 1kg having speed of 50 m/s, hit a iron nail of mass 200 gm. If specific heat of iron is 0.105 cal/gm°C and half the energy is converted into heat, the raise in temperature of nail is [RPMT 1995]

Joint Entrance Exam - Main (JEE Main) Physics in Joint Entrance Exam - Main (JEE Main) 1 year ago

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\[W=JQ\] Þ \[\frac{1}{2}\LEFT( \frac{1}{2}M{{v}^{2}} \right)=J(m.C.\Delta \theta )\] Þ \[\frac{1}{4}\TIMES 1\times {{(50)}^{2}}=4.2[200\times 0.105\times \Delta \theta ]\]Þ \[\Delta \theta =7.1{}^\circ C\]

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