B] We know that, magnetic dipole moment \[M=NiA\,\cos \,\theta \] i.e.,  \[M\propto \,\cos \,\theta \] When TWO magnetic fields are inclined at an ANGLE of \[75{}^\circ \] the equilibrium will be at \[39{}^\circ \], so \[\cos \theta =\cos \,(75{}^\circ -30{}^\circ )=\,\cos \,45{}^\circ =\frac{1}{\sqrt{2}}\] \[\frac{x}{\sqrt{2}}=\frac{15}{2}\,\,\therefore \,\,\,x\approx 11\]

"> B] We know that, magnetic dipole moment \[M=NiA\,\cos \,\theta \] i.e.,  \[M\propto \,\cos \,\theta \] When TWO magnetic fields are inclined at an ANGLE of \[75{}^\circ \] the equilibrium will be at \[39{}^\circ \], so \[\cos \theta =\cos \,(75{}^\circ -30{}^\circ )=\,\cos \,45{}^\circ =\frac{1}{\sqrt{2}}\] \[\frac{x}{\sqrt{2}}=\frac{15}{2}\,\,\therefore \,\,\,x\approx 11\]

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A magnetic dipole is acted upon by two magnetic Fields which are inclined to each other at an angle of \[{{75}^{o}}\]. One of the fields has a magnitude of 15 mT. The dipole attains stable equilibrium at an angle of \[{{30}^{o}}\]with this field. The magnitude of the other field (in mT) is close to:

Joint Entrance Exam - Main (JEE Main) Physics in Joint Entrance Exam - Main (JEE Main) . 9 months ago

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[B] We know that, magnetic dipole moment \[M=NiA\,\cos \,\theta \] i.e.,  \[M\propto \,\cos \,\theta \] When TWO magnetic fields are inclined at an ANGLE of \[75{}^\circ \] the equilibrium will be at \[39{}^\circ \], so \[\cos \theta =\cos \,(75{}^\circ -30{}^\circ )=\,\cos \,45{}^\circ =\frac{1}{\sqrt{2}}\] \[\frac{x}{\sqrt{2}}=\frac{15}{2}\,\,\therefore \,\,\,x\approx 11\]

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Posted on 22 Aug 2024, this text provides information on Joint Entrance Exam - Main (JEE Main) related to Physics in Joint Entrance Exam - Main (JEE Main). Please note that while accuracy is prioritized, the data presented might not be entirely correct or up-to-date. This information is offered for general knowledge and informational purposes only, and should not be considered as a substitute for professional advice.

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