PIPE \[{{N}_{1}}=\frac{v}{4l}\RIGHTARROW 250=\frac{v}{4\times 0.2}\]\[\Rightarrow v=200\,m/s\]

"> PIPE \[{{N}_{1}}=\frac{v}{4l}\RIGHTARROW 250=\frac{v}{4\times 0.2}\]\[\Rightarrow v=200\,m/s\]

">

A resonance air column of length 20 cm resonates with a tuning fork of frequency 250 Hz. The speed of sound in air is [AFMC 1999; BHU 2000; CPMT 2001]

Joint Entrance Exam - Main (JEE Main) Physics in Joint Entrance Exam - Main (JEE Main) . 8 months ago

  665   0   0   0   0 tuteeHUB earn credit +10 pts

5 Star Rating 1 Rating

For closed PIPE \[{{N}_{1}}=\frac{v}{4l}\RIGHTARROW 250=\frac{v}{4\times 0.2}\]\[\Rightarrow v=200\,m/s\]

Posted on 17 Aug 2024, this text provides information on Joint Entrance Exam - Main (JEE Main) related to Physics in Joint Entrance Exam - Main (JEE Main). Please note that while accuracy is prioritized, the data presented might not be entirely correct or up-to-date. This information is offered for general knowledge and informational purposes only, and should not be considered as a substitute for professional advice.

Take Quiz To Earn Credits!

Turn Your Knowledge into Earnings.

tuteehub_quiz

Tuteehub forum answer Answers

Post Answer

No matter what stage you're at in your education or career, TuteeHub will help you reach the next level that you're aiming for. Simply,Choose a subject/topic and get started in self-paced practice sessions to improve your knowledge and scores.