1}^{2}+r_{2}^{2}}=\sqrt{9+16}=5\ CM\]

"> 1}^{2}+r_{2}^{2}}=\sqrt{9+16}=5\ CM\]

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A soap bubble in vacuum has a radius of 3 cm and another soap bubble in vacuum has a radius of 4 cm. If the two bubbles coalesce under isothermal condition, then the radius of the new bubble is              [MP PMT/PET 1998; JIPMER 2000]

Joint Entrance Exam - Main (JEE Main) Physics in Joint Entrance Exam - Main (JEE Main) 10 months ago

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\[r=\sqrt{r_{1}^{2}+r_{2}^{2}}=\sqrt{9+16}=5\ CM\]

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Posted on 05 Sep 2024, this text provides information on Joint Entrance Exam - Main (JEE Main) related to Physics in Joint Entrance Exam - Main (JEE Main). Please note that while accuracy is prioritized, the data presented might not be entirely correct or up-to-date. This information is offered for general knowledge and informational purposes only, and should not be considered as a substitute for professional advice.

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