GIVEN to a SPHERE at LOWEST point = potential energy at the height of SUSPENSION                         Þ \[\frac{1}{2}m{{v}^{2}}=mgl\]             \\[v=\sqrt{2gl}\]

"> GIVEN to a SPHERE at LOWEST point = potential energy at the height of SUSPENSION                         Þ \[\frac{1}{2}m{{v}^{2}}=mgl\]             \\[v=\sqrt{2gl}\]

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A sphere is suspended by a thread of length \[l\]. What minimum horizontal velocity has to be imparted the ball for it to reach the height of the suspension  [ISM Dhanbad 1994]

Joint Entrance Exam - Main (JEE Main) Physics in Joint Entrance Exam - Main (JEE Main) . 9 months ago

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Kinetic energy GIVEN to a SPHERE at LOWEST point = potential energy at the height of SUSPENSION                         Þ \[\frac{1}{2}m{{v}^{2}}=mgl\]             \\[v=\sqrt{2gl}\]

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