KG ice melts out of m kg then by using \[W=JQ\] Þ \[mgh=J({m}'L)\]. Hence fraction of ice melts \[=\frac{{{m}'}}{m}=\frac{
GH
}{JL}=\frac{9.8\times 1000}{4.18\times 80}=\frac{1}{
33
}\]