HDG)\] Þ\[3{{P}_{0}}+\frac{3H}{2}dg=2{{P}_{0}}+2hdg\] \[\RIGHTARROW h=\frac{2{{P}_{0}}}{dg}=\frac{2\TIMES {{10}^{5}}}{{{10}^{3}}\times 10}=20\ m\]