1 ´ 10?6´ (3 ´ 108)2 = 9 ´ 1010 W = 9 ´ 107 KW.

"> 1 ´ 10?6´ (3 ´ 108)2 = 9 ´ 1010 W = 9 ´ 107 KW.

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In a nuclear reactor, the fuel is consumed at the rate of 1 mg/s. The power generated in kilowatt is [DCE 2003]

Joint Entrance Exam - Main (JEE Main) Physics in Joint Entrance Exam - Main (JEE Main) 1 year ago

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Power \[P=\frac{Energy}{time}=\frac{m{{c}^{2}}}{t},\]= 1 ´ 10?6´ (3 ´ 108)2 = 9 ´ 1010 W = 9 ´ 107 KW.

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Posted on 24 Aug 2024, this text provides information on Joint Entrance Exam - Main (JEE Main) related to Physics in Joint Entrance Exam - Main (JEE Main). Please note that while accuracy is prioritized, the data presented might not be entirely correct or up-to-date. This information is offered for general knowledge and informational purposes only, and should not be considered as a substitute for professional advice.

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