ACCELERATED, HENCE the reading of the balance will be EQUAL to the true WEIGHT.                         \[R=mg=2g\ Newton\] or  2 kg

"> ACCELERATED, HENCE the reading of the balance will be EQUAL to the true WEIGHT.                         \[R=mg=2g\ Newton\] or  2 kg

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In the above problem, if the lift moves up with a constant velocity of 2 m/sec, the reading on the balance will be [NCERT 1977]            

Joint Entrance Exam - Main (JEE Main) Physics in Joint Entrance Exam - Main (JEE Main) . 9 months ago

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The lift is not ACCELERATED, HENCE the reading of the balance will be EQUAL to the true WEIGHT.                         \[R=mg=2g\ Newton\] or  2 kg

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Posted on 13 Sep 2024, this text provides information on Joint Entrance Exam - Main (JEE Main) related to Physics in Joint Entrance Exam - Main (JEE Main). Please note that while accuracy is prioritized, the data presented might not be entirely correct or up-to-date. This information is offered for general knowledge and informational purposes only, and should not be considered as a substitute for professional advice.

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