TEXT{mix}}}=\frac{{{m}_{W}}{{\theta }_{W}}-\frac{{{m}_{\,i}}{{L}_{\,i}}}{{{c}_{W}}}}{{{m}_{\,i}}+{{m}_{W}}}\]            \[\because \,{{m}_{i}}={{m}_{W}}\]Þ\[{{\theta }_{mix}}=\frac{{{\theta }_{W}}-\frac{{{L}_{i}}}{{{c}_{W}}}}{2}\]\[=\frac{80+0-\frac{336}{4.2}}{2}=0{}^\CIRC C\]

"> TEXT{mix}}}=\frac{{{m}_{W}}{{\theta }_{W}}-\frac{{{m}_{\,i}}{{L}_{\,i}}}{{{c}_{W}}}}{{{m}_{\,i}}+{{m}_{W}}}\]            \[\because \,{{m}_{i}}={{m}_{W}}\]Þ\[{{\theta }_{mix}}=\frac{{{\theta }_{W}}-\frac{{{L}_{i}}}{{{c}_{W}}}}{2}\]\[=\frac{80+0-\frac{336}{4.2}}{2}=0{}^\CIRC C\]

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One kilogram of ice at 0°C is mixed with one kilogram of water at 80°C. The final temperature of the mixture is (Take : specific heat of water\[=4200\,J\,k{{g}^{-1}}\,{{K}^{-1}}\], latent heat of ice \[=336\,kJ\,k{{g}^{-1}})\]    [KCET 2002]

Joint Entrance Exam - Main (JEE Main) Physics in Joint Entrance Exam - Main (JEE Main) 11 months ago

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\[{{\theta }_{\TEXT{mix}}}=\frac{{{m}_{W}}{{\theta }_{W}}-\frac{{{m}_{\,i}}{{L}_{\,i}}}{{{c}_{W}}}}{{{m}_{\,i}}+{{m}_{W}}}\]            \[\because \,{{m}_{i}}={{m}_{W}}\]Þ\[{{\theta }_{mix}}=\frac{{{\theta }_{W}}-\frac{{{L}_{i}}}{{{c}_{W}}}}{2}\]\[=\frac{80+0-\frac{336}{4.2}}{2}=0{}^\CIRC C\]

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Posted on 21 Aug 2024, this text provides information on Joint Entrance Exam - Main (JEE Main) related to Physics in Joint Entrance Exam - Main (JEE Main). Please note that while accuracy is prioritized, the data presented might not be entirely correct or up-to-date. This information is offered for general knowledge and informational purposes only, and should not be considered as a substitute for professional advice.

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