BODY diagram of POINT B Let the tension in the section BC and BF are \[{{T}_{1}}\] and \[{{T}_{2}}\]RESPECTIVELY. From Lami's theorem \[\frac{{{T}_{1}}}{\sin 120{}^\circ }=\frac{{{T}_{2}}}{\sin 120{}^\circ }=\frac{T}{\sin 120{}^\circ }\] Þ \[T={{T}_{1}}={{T}_{2}}=10\ N.\]