VAREPSILON }_{0}}}{d}=10\mu F\] \[{{C}_{1}}=\frac{A{{\varepsilon }_{0}}}{d-t+\frac{t}{k}}=\frac{A{{\varepsilon }_{0}}}{d-\frac{d}{2}+\frac{d}{2k}}=\frac{A{{\varepsilon }_{0}}}{\frac{d}{2}\LEFT( 1+\frac{1}{2} \RIGHT)}=\frac{4}{3}.\frac{A{{\varepsilon }_{0}}}{d}\] \ \[{{C}_{1}}=\frac{4}{3}\times 10=13.33\mu F\]