CUTTING SPRING in four equal parts force constant (K) of each parts becomes four times \[\LEFT( \because \,k\propto \frac{1}{l} \RIGHT)\] so by using \[T=2\pi \sqrt{\frac{m}{K}};\] time period will be half i.e. \[T'=T/2\]

"> CUTTING SPRING in four equal parts force constant (K) of each parts becomes four times \[\LEFT( \because \,k\propto \frac{1}{l} \RIGHT)\] so by using \[T=2\pi \sqrt{\frac{m}{K}};\] time period will be half i.e. \[T'=T/2\]

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The time period of a mass suspended from a spring is T. If the spring is cut into four equal parts and the same mass is suspended from one of the parts, then the new time period will be        [MP PMT 2002; CBSE PMT 2003]

Joint Entrance Exam - Main (JEE Main) Physics in Joint Entrance Exam - Main (JEE Main) . 8 months ago

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By CUTTING SPRING in four equal parts force constant (K) of each parts becomes four times \[\LEFT( \because \,k\propto \frac{1}{l} \RIGHT)\] so by using \[T=2\pi \sqrt{\frac{m}{K}};\] time period will be half i.e. \[T'=T/2\]

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Posted on 12 Sep 2024, this text provides information on Joint Entrance Exam - Main (JEE Main) related to Physics in Joint Entrance Exam - Main (JEE Main). Please note that while accuracy is prioritized, the data presented might not be entirely correct or up-to-date. This information is offered for general knowledge and informational purposes only, and should not be considered as a substitute for professional advice.

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