REST, \[T=2\pi \SQRT{L/g}\] If ACCELERATION becomes g/4 then \[{T}'=2\pi \sqrt{\FRAC{l}{g/4}}=2\pi \sqrt{\frac{4l}{g}}=2\times T\]

"> REST, \[T=2\pi \SQRT{L/g}\] If ACCELERATION becomes g/4 then \[{T}'=2\pi \sqrt{\FRAC{l}{g/4}}=2\pi \sqrt{\frac{4l}{g}}=2\times T\]

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There is a simple pendulum hanging from the ceiling of a lift. When the lift is stand still, the time period of the pendulum is T. If the resultant acceleration becomes \[g/4,\] then the new time period of the pendulum is             [DCE 2004]

Joint Entrance Exam - Main (JEE Main) Physics in Joint Entrance Exam - Main (JEE Main) . 10 months ago

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When lift is at REST, \[T=2\pi \SQRT{L/g}\] If ACCELERATION becomes g/4 then \[{T}'=2\pi \sqrt{\FRAC{l}{g/4}}=2\pi \sqrt{\frac{4l}{g}}=2\times T\]

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