C] Given that \[\frac{\DELTA l}{l}\times\] 100=+1%and \[\frac{\Delta T}{T}\times\] 100=-3% PERCENTAGE error in the measurement of G is \[\left[ \frac{4{{\pi }^{2}}l}{{{T}^{2}}} \right]=100\times \frac{\Delta l}{l}-2\times \frac{\Delta T}{T}\times 100\] =1%-2[-3%]=+7%

"> C] Given that \[\frac{\DELTA l}{l}\times\] 100=+1%and \[\frac{\Delta T}{T}\times\] 100=-3% PERCENTAGE error in the measurement of G is \[\left[ \frac{4{{\pi }^{2}}l}{{{T}^{2}}} \right]=100\times \frac{\Delta l}{l}-2\times \frac{\Delta T}{T}\times 100\] =1%-2[-3%]=+7%

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While measuring the acceleration due to gravity by a simple pendulum, a student makes a positive error of 1% in the length of the pendulum and a negative error of 3% in the value of time period. His percentage error in the measurement of g by the relation \[g=4\pi _{{}}^{2}(l/T_{{}}^{2})\] will be

Joint Entrance Exam - Main (JEE Main) Physics in Joint Entrance Exam - Main (JEE Main) . 9 months ago

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[C] Given that \[\frac{\DELTA l}{l}\times\] 100=+1%and \[\frac{\Delta T}{T}\times\] 100=-3% PERCENTAGE error in the measurement of G is \[\left[ \frac{4{{\pi }^{2}}l}{{{T}^{2}}} \right]=100\times \frac{\Delta l}{l}-2\times \frac{\Delta T}{T}\times 100\] =1%-2[-3%]=+7%

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Posted on 09 Sep 2024, this text provides information on Joint Entrance Exam - Main (JEE Main) related to Physics in Joint Entrance Exam - Main (JEE Main). Please note that while accuracy is prioritized, the data presented might not be entirely correct or up-to-date. This information is offered for general knowledge and informational purposes only, and should not be considered as a substitute for professional advice.

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