C] Given that \[\frac{\DELTA l}{l}\times\] 100=+1%and \[\frac{\Delta T}{T}\times\] 100=-3% PERCENTAGE error in the measurement of G is \[\left[ \frac{4{{\pi }^{2}}l}{{{T}^{2}}} \right]=100\times \frac{\Delta l}{l}-2\times \frac{\Delta T}{T}\times 100\] =1%-2[-3%]=+7%