HIGH:PMOS is OFFNMOS is ON then y = Q̅⇒If P = lowPMOS is ONNMOS is OFF then y = QThe truth table of the above will be as SHOWN:\(\left. {\BEGIN{array}{*{20}{C}} P&Q&Y\\ 0&0&0\\ 0&1&1\\ 1&0&1\\ 1&1&0 \end{array}} \right\}\) So, Y = P̅ Q + P Q̅= P ⊕ QSo, Ex – OR Operation is being performed.

"> HIGH:PMOS is OFFNMOS is ON then y = Q̅⇒If P = lowPMOS is ONNMOS is OFF then y = QThe truth table of the above will be as SHOWN:\(\left. {\BEGIN{array}{*{20}{C}} P&Q&Y\\ 0&0&0\\ 0&1&1\\ 1&0&1\\ 1&1&0 \end{array}} \right\}\) So, Y = P̅ Q + P Q̅= P ⊕ QSo, Ex – OR Operation is being performed.

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For the circuit shown in the figure, P and Q are the inputs and Y is the output.The logic implemented by the circuit is

Logical and Verbal Reasoning Logic in Logical and Verbal Reasoning . 7 months ago

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⇒ If P = HIGH:PMOS is OFFNMOS is ON then y = Q̅⇒If P = lowPMOS is ONNMOS is OFF then y = QThe truth table of the above will be as SHOWN:\(\left. {\BEGIN{array}{*{20}{C}} P&Q&Y\\ 0&0&0\\ 0&1&1\\ 1&0&1\\ 1&1&0 \end{array}} \right\}\) So, Y = P̅ Q + P Q̅= P ⊕ QSo, Ex – OR Operation is being performed.

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