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Login3 The sides of a quadrilateral, taken in order are 5, 12, 14 and 15 metres respectively, andthe angle contained by the first two sides is a right angle. Find its area.
Math Secondary School in Math 1 year ago
Step-by-step explanation:Here, AB = 5 m, BC = 12 m, CD = 14 m and DA = 15 m Join the diagonal AC. Now, area of △ABC = 1/2 x AB x BC = 1/2 x 5 x 12 = 30 Area of △ABC is 30 M2 In △ABC, (RIGHT triangle). From Pythagoras theorem, AC2 = AB2 + BC2 AC2 = 52 + 122 AC2 = 25 + 144 = 169 or AC = 13 Now in △ADC, All sides are know, APPLY Heron’s Formula: Where a, b and c are sides of a triangle. PERIMETER of △ADC = 2s = AD + DC + AC 2s = 15 m + 14 m + 13 m s = 21 m Area of △ADC = 84 m^2 Area of quadrilateral ABCD = Area of △ABC + Area of △ADC = (30 + 84) m2 = 114 m^2Hope it helps!
Posted on 03 Aug 2024, this text provides information on Math related to Secondary School in Math. Please note that while accuracy is prioritized, the data presented might not be entirely correct or up-to-date. This information is offered for general knowledge and informational purposes only, and should not be considered as a substitute for professional advice.
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