If α and β are the zeros of the quadratic polynomial f(x)= x² - x - 4 , find the value of (1/α) + (1/β) - αβ .

α and β are the zeroes of the quadratic polynomial f(x)= x² - x - 4 On comparing with ax² + bx + c, a = 1 , B= -1 , c= -4 Sum of the zeroes = −COEFFICIENT of x / coefficient of x² α + β  = -b/a = -(-1)/1 = 1   α + β = 1……………………..(1) Product of the zeroes = constant term/ Coefficient of x² αβ = c/a = -4/1 = - 4 αβ = - 4 ……………………(2) 1/α + 1/β  - αβ = [( α+β) / αβ] - αβ By Substituting the value from eq 1 & eq2 , we get   = [ 1/−4 ]  - (- 4) = −1/4 + 4 = (− 1 + 16)/4 =  15/ 4 1/α + 1/β  - αβ  = 15/4 Hence, the value of  1/α + 1/β  - αβ  = 15/4 HOPE THIS ANSWER WILL HELP YOU…  Some more questions :   If are the ZEROS of the quadratic polynomial ,find the value of brainly.in/question/6880650 If are the zeros of the quadratic polynomial ,find the value of brainly.in/question/6880659