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LoginMath Secondary School in Math . 10 months ago
Product of TWO numbers is 194400 .Step-by-step EXPLANATION:Let the LCM of two numbers be L and HCF of two numbers be HFirst condition states that sum of LCM and HCF of two numbers is 1260, i.e.; L + H = 1260 L = 1260 - H ---------- [Equation 1]Second condition states that LCM is 900 more than their HCF, i.e.; L = 900 + H 1260 - H = 900 + H {using equation 1} 2*H = 1260 - 900 H = 360/2 = 180 Putting value of H in equation 1, we get; L = 1260 - 180 = 1080 So, HCF of two numbers = 180 and LCM of two numbers = 1080 Now, Product of two numbers = HCF * LCM = 180 * 1080 = 194400 .
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