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LoginNumber of natural numbers upto one lakh which contains 1, 2, 3 exactly once and remaining digits any time is
Math Secondary School in Math . 11 months ago
+10 pts
of natural numbers upto one lakh which contains 1, 2, 3 exactly once and REMAINING digits any time is 2940Step-by-step explanation:Step 1:Given data:100000 we can say that 3 digit 3! = 6 since we know that 4 digit without zero and with zero Step 2:5 digit = without zero with 1 zero = with 2 zero Thus the Number of natural numbers upto one lakh which contains 1, 2, 3 exactly once and remaining digits any time is calculated by the following total = 6 + 144 + 18 + 2160 + 576 + 36 = 2940 Therefore the ANSWER is 2940To know more about natural number simplifications, VISIT:Find the sum of all natural numbers from 1 to 120 which are divisible by 3brainly.in/question/14624143Find sum of FIRST 24 natural numbers brainly.in/question/12596074
Posted on 17 Jul 2024, this text provides information on Math related to Secondary School in Math. Please note that while accuracy is prioritized, the data presented might not be entirely correct or up-to-date. This information is offered for general knowledge and informational purposes only, and should not be considered as a substitute for professional advice.
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