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LoginMath Secondary School in Math 1 year ago
Move all the terms containing a logarithm to the left side of the equation. ln ( 1 + x ) − ln ( 1 + x ) = ( 1 + x ) 2 − 3 USE the QUOTIENT property of logarithms, log b ( x ) − log b ( y ) = log b ( x y ) . ln ( 1 + x 1 + x ) = ( 1 + x ) 2 − 3 Cancel the common factor of 1 + x . Tap for more steps... ln ( 1 ) = ( 1 + x ) 2 − 3 The natural logarithm of 1 is 0 . 0 = ( 1 + x ) 2 − 3 SIMPLIFY ( 1 + x ) 2 − 3 . Tap for more steps... 0 = 2 x + x 2 − 2 Since x is on the right side of the equation, SWITCH the sides so it is on the left side of the equation. 2 x + x 2 − 2 = 0 Use the quadratic formula to find the solutions. − b ± √ b 2 − 4 ( a C ) 2 a Substitute the values a = 1 , b = 2 , and c = − 2 into the quadratic formula and solve for x . − 2 ± √ 2 2 − 4 ⋅ ( 1 ⋅ − 2 ) 2 ⋅ 1 Simplify. Tap for more steps... x = − 1 ± √ 3 The final answer is the combination of both solutions. x = − 1 + √ 3 , − 1 − √ 3 Exclude the solutions that do not make ln ( 1 + x ) = ln ( 1 + x ) + ( 1 + x ) 2 − 3 true. x = − 1 + √ 3 The result can be shown in multiple forms. Exact Form: x = − 1 + √ 3 Decimal Form: x = 0.73205080 …
Posted on 09 Sep 2024, this text provides information on Math related to Secondary School in Math. Please note that while accuracy is prioritized, the data presented might not be entirely correct or up-to-date. This information is offered for general knowledge and informational purposes only, and should not be considered as a substitute for professional advice.
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