Sohan can do a piece of work in 16 days and Rohan in 24 days. They take the help of Mohanand three together finish the work in 6 days.If total remuneration for the work is 80, thenamount each will receive in proposition to thework done by each is?​

ot Rs 30 and ROHAN got Rs 20 and mohan got Rs 30Solution:Given that,SOHAN can do a piece of work in 16 days and  Rohan in 24 daysThey take the help of Mohan  and three together finish the work in 6 daysFind the days taken by MohanLet "x" be the days taken by Mohan Therefore,Mohan can do a piece of work in 16 daysSohan can do a piece of work in 16 daysRohan in 24 daysThey work in the ratio as:Sohan : Rohan : MohanLet the work efficiency of sohan be 3xLet the work efficiency of rohan be 2xLet the work efficiency of mohan be 3xTotal remuneration for the work is 80Therefore,3x + 2x + 3x = 808x = 80x = 10Thus,AMOUNT received by Sohan = 3x = 3(10) = 30Amount received by Rohan = 2x = 2(10) = 20Amount received by Mohan = 3x = 3(10) = 30Thus sohan got Rs 30 and rohan got Rs 20 and mohan got Rs 30Learn more about time and workMohan and sohan can do a job in 12 days. Sohan alone can do this job in 28 days. In how many days can mohan do this job?brainly.in/question/8579564Mohan can do certain job in 12 Days sohan is 60% More efficient than mohan find number of days taken by sohan to finish the jobbrainly.in/question/75340