C) LET number be\[x\] Then \[8.9\times x=31.15\,\,\therefore x\] \[=\FRAC{31.156}{8.9}=\frac{\overset{\,\,\,\,\,\,\,\,\,\,35}{\mathop{\bcancel{3115}}}\,}{\underset{\,\,\,\,\,\,10}{\mathop{\bcancel{890}}}\,}=\frac{35}{10}=3.5\]