2}}{{H}_{5}}OH\LEFT( l \right)+3{{O}_{2}}\left( g \right)\xrightarrow{{}}\] \[2C{{O}_{2}}\left( g \right)+3{{H}_{2}}O\left( l \right)\] BOMB calorimeter GIVES\[\Delta U\] of the reaction Given, \[\Delta U=-1364.47\text{ }kJ\text{ }mo{{l}^{-1}}\] \[\Delta {{n}_{g}}=-1\] \[\Delta H=\Delta U+\Delta {{n}_{g}}RT\]\[=-\,1364.47-\frac{1\times 8.314\times 298}{1000}\]\[=-1366.93\text{ }kJ\text{ }mo{{l}^{-1}}\]

"> 2}}{{H}_{5}}OH\LEFT( l \right)+3{{O}_{2}}\left( g \right)\xrightarrow{{}}\] \[2C{{O}_{2}}\left( g \right)+3{{H}_{2}}O\left( l \right)\] BOMB calorimeter GIVES\[\Delta U\] of the reaction Given, \[\Delta U=-1364.47\text{ }kJ\text{ }mo{{l}^{-1}}\] \[\Delta {{n}_{g}}=-1\] \[\Delta H=\Delta U+\Delta {{n}_{g}}RT\]\[=-\,1364.47-\frac{1\times 8.314\times 298}{1000}\]\[=-1366.93\text{ }kJ\text{ }mo{{l}^{-1}}\]

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For complete combustion of ethanol, \[{{C}_{2}}{{H}_{5}}OH\left( l \right)+3{{O}_{2}}\left( g \right)\xrightarrow{{}}2C{{O}_{2}}\left( g \right)+3{{H}_{2}}O\left( l \right),\] the amount of heat produced as measured in bomb calorimeter, is \[1364.47\text{ }kJ\text{ }mo{{l}^{-1}}\] at\[25{}^\circ C\]. Assuming ideality the enthalpy of combustion, \[{{\Delta }_{c}}H\], for the reaction will be: \[\left( R=8.314\text{ }kJ\,mo{{l}^{-1}} \right)\]

NEET Chemistry in NEET 1 year ago

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[a] \[{{C}_{2}}{{H}_{5}}OH\LEFT( l \right)+3{{O}_{2}}\left( g \right)\xrightarrow{{}}\] \[2C{{O}_{2}}\left( g \right)+3{{H}_{2}}O\left( l \right)\] BOMB calorimeter GIVES\[\Delta U\] of the reaction Given, \[\Delta U=-1364.47\text{ }kJ\text{ }mo{{l}^{-1}}\] \[\Delta {{n}_{g}}=-1\] \[\Delta H=\Delta U+\Delta {{n}_{g}}RT\]\[=-\,1364.47-\frac{1\times 8.314\times 298}{1000}\]\[=-1366.93\text{ }kJ\text{ }mo{{l}^{-1}}\]

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Posted on 03 Aug 2024, this text provides information on NEET related to Chemistry in NEET. Please note that while accuracy is prioritized, the data presented might not be entirely correct or up-to-date. This information is offered for general knowledge and informational purposes only, and should not be considered as a substitute for professional advice.

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