LAW \[{{\Delta }_{f}}{{H}^{{}^\circ }}={{\Delta }_{SUB}}H+\frac{1}{2}\Delta dissH+I.E.+E.A+{{\Delta }_{lattice}}H\] \[-617=161+520+77+E.A.+\left( -1047 \right)\] \[E.A.=-617+289=-328\text{ }kJ\text{ }MO{{l}^{-1}}\]             \[\therefore \] electron affinity of FLUORINE \[=-328\text{ }kJ\,mo{{l}^{-1}}\]

"> LAW \[{{\Delta }_{f}}{{H}^{{}^\circ }}={{\Delta }_{SUB}}H+\frac{1}{2}\Delta dissH+I.E.+E.A+{{\Delta }_{lattice}}H\] \[-617=161+520+77+E.A.+\left( -1047 \right)\] \[E.A.=-617+289=-328\text{ }kJ\text{ }MO{{l}^{-1}}\]             \[\therefore \] electron affinity of FLUORINE \[=-328\text{ }kJ\,mo{{l}^{-1}}\]

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Given Reaction Energy Change (in KJ) \[Li\left( s \right)\to Li\left( g \right)\] 161 \[Li\left( g \right)\to L{{i}^{+}}\left( g \right)\] 520 \[\frac{1}{2}{{F}_{2}}(g)\to F(g)\] 77 \[F\left( g \right)+{{e}^{-}}\to {{F}^{-}}\left( g \right)\] Electron gain enthalpy \[L{{i}^{+}}(g)+{{F}^{-}}(g)\to LiF(s)\] -1047 \[Li(s)+\frac{1}{2}{{F}_{2}}(g)\to LiF(s)\] -617 Based on data provided, the value of electron gain enthalpy of fluorine would be:

NEET Chemistry in NEET . 9 months ago

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[c] Applying Hess's LAW \[{{\Delta }_{f}}{{H}^{{}^\circ }}={{\Delta }_{SUB}}H+\frac{1}{2}\Delta dissH+I.E.+E.A+{{\Delta }_{lattice}}H\] \[-617=161+520+77+E.A.+\left( -1047 \right)\] \[E.A.=-617+289=-328\text{ }kJ\text{ }MO{{l}^{-1}}\]             \[\therefore \] electron affinity of FLUORINE \[=-328\text{ }kJ\,mo{{l}^{-1}}\]

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Posted on 01 Sep 2024, this text provides information on NEET related to Chemistry in NEET. Please note that while accuracy is prioritized, the data presented might not be entirely correct or up-to-date. This information is offered for general knowledge and informational purposes only, and should not be considered as a substitute for professional advice.

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