MN{{O}_{
2
}},Pb{{O}_{2}}\] and \[
BAO
\] will not give \[{{H}_{2}}{{O}_{2}}\] with \[HCl.Mn{{O}_{2}}\] and \[Pb{{O}_{2}}\] will give \[C{{
L
}_{2}}\] and \[BaO\] will
REACT
with \[HCl\] to give \[BaC{{l}_{2}}\] and water.