DELTA G_{f}^{{}^\circ }\] of most of the sulphides are greater than those of \[C{{S}_{2}}\] and\[{{H}_{2}}S\], therefore neither C nor H can reduce METAL sulphide to metal. Further, the standard free energies of FORMATION of oxide are much less than those of \[S{{O}_{2}}.\] HENCE oxidation of metal sulphides to metal oxide is thermodynamically favourable.

"> DELTA G_{f}^{{}^\circ }\] of most of the sulphides are greater than those of \[C{{S}_{2}}\] and\[{{H}_{2}}S\], therefore neither C nor H can reduce METAL sulphide to metal. Further, the standard free energies of FORMATION of oxide are much less than those of \[S{{O}_{2}}.\] HENCE oxidation of metal sulphides to metal oxide is thermodynamically favourable.

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Which of the following statements, about the advantage of roasting of sulphide ore before reduction is not true?

NEET Chemistry in NEET 1 year ago

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[d] The sulphide ore is roasted to oxide before reduction because the \[\DELTA G_{f}^{{}^\circ }\] of most of the sulphides are greater than those of \[C{{S}_{2}}\] and\[{{H}_{2}}S\], therefore neither C nor H can reduce METAL sulphide to metal. Further, the standard free energies of FORMATION of oxide are much less than those of \[S{{O}_{2}}.\] HENCE oxidation of metal sulphides to metal oxide is thermodynamically favourable.

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Posted on 13 Aug 2024, this text provides information on NEET related to Chemistry in NEET. Please note that while accuracy is prioritized, the data presented might not be entirely correct or up-to-date. This information is offered for general knowledge and informational purposes only, and should not be considered as a substitute for professional advice.

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