REQUIRES that \[\Lambda PE+KE=0\] or         \[\frac{1}{2}k{{x}^{2}}-\frac{1}{2}mv_{0}^{2}=0\]   \[\THEREFORE \] \[x=\SQRT{\frac{m}{k}}{{V}_{0}}\]   \[\therefore \,\,\,\,\,\,{{F}_{\max }}=kx=\sqrt{mk}{{v}_{0}}\]   or        \[{{F}_{\max }}\propto \sqrt{k}\propto \sqrt{m}\propto {{v}_{0}}\]

"> REQUIRES that \[\Lambda PE+KE=0\] or         \[\frac{1}{2}k{{x}^{2}}-\frac{1}{2}mv_{0}^{2}=0\]   \[\THEREFORE \] \[x=\SQRT{\frac{m}{k}}{{V}_{0}}\]   \[\therefore \,\,\,\,\,\,{{F}_{\max }}=kx=\sqrt{mk}{{v}_{0}}\]   or        \[{{F}_{\max }}\propto \sqrt{k}\propto \sqrt{m}\propto {{v}_{0}}\]

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A block of mass m moving with a velocity \[{{v}_{0}}\]on a smooth horizontal floor collides with a light spring of stiffhess k that is rigidly fixed horizontally with a vertical wall. If the maximum force imparted by the spring on the block is F, then

NEET Physics in NEET . 2 months ago

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[d] Energy conservation between the positions A and B REQUIRES that \[\Lambda PE+KE=0\] or         \[\frac{1}{2}k{{x}^{2}}-\frac{1}{2}mv_{0}^{2}=0\]   \[\THEREFORE \] \[x=\SQRT{\frac{m}{k}}{{V}_{0}}\]   \[\therefore \,\,\,\,\,\,{{F}_{\max }}=kx=\sqrt{mk}{{v}_{0}}\]   or        \[{{F}_{\max }}\propto \sqrt{k}\propto \sqrt{m}\propto {{v}_{0}}\]

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