V=constant\] When \[F=\mu mg\] net FORCE on BLOCK becomes ZERO, i.e., it has maximum or TERMINAL velocity \[\therefore \] \[p=(\mu mg){{V}_{\max }}\] \[\therefore \] \[{{V}_{\max }}=\frac{P}{\mu mg}\]

"> V=constant\] When \[F=\mu mg\] net FORCE on BLOCK becomes ZERO, i.e., it has maximum or TERMINAL velocity \[\therefore \] \[p=(\mu mg){{V}_{\max }}\] \[\therefore \] \[{{V}_{\max }}=\frac{P}{\mu mg}\]

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A block of mass m is pulled by a constant power P placed on a rough horizontal plane. The friction coefficient between the block and the surface is \[\text{I}{{\text{F}}_{\text{3}}}\]. Maximum velocity of the block will be

NEET Physics in NEET . 9 months ago

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[d] \[\therefore P=F.V=constant\] When \[F=\mu mg\] net FORCE on BLOCK becomes ZERO, i.e., it has maximum or TERMINAL velocity \[\therefore \] \[p=(\mu mg){{V}_{\max }}\] \[\therefore \] \[{{V}_{\max }}=\frac{P}{\mu mg}\]

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Posted on 17 Aug 2024, this text provides information on NEET related to Physics in NEET. Please note that while accuracy is prioritized, the data presented might not be entirely correct or up-to-date. This information is offered for general knowledge and informational purposes only, and should not be considered as a substitute for professional advice.

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