VOLUME of CUBE = \[{{a}^{3}}\]          Surface area of cube = \[6{{a}^{2}}\]          ACCORDING to problem A3 = 6a2 Þ a = 6 \\[V={{a}^{3}}=216\,units\]. "> VOLUME of CUBE = \[{{a}^{3}}\]          Surface area of cube = \[6{{a}^{2}}\]          ACCORDING to problem A3 = 6a2 Þ a = 6 \\[V={{a}^{3}}=216\,units\]. ">
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A cube has numerically equal volume and surface area. The volume of such a cube is   [CPMT 1971, 74]

NEET Physics in NEET 10 months ago

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VOLUME of CUBE = \[{{a}^{3}}\]          Surface area of cube = \[6{{a}^{2}}\]          ACCORDING to problem A3 = 6a2 Þ a = 6 \\[V={{a}^{3}}=216\,units\].
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