VAREPSILON }_{0}}A}{d}\] ...(i) where \[{{\varepsilon }_{0}}=\] ELECTRIC PERMITTIVITY of free SPACE K = dielectric constant A = area of each plate of capacitor d = distance between two plates When dielectric (oil) is removed, so capacitance \[{{C}_{0}}=\frac{{{\varepsilon }_{0}}A}{d}\] (ii) Comparing Eqs. (i) and (ii), we GET \[C=K{{C}_{0}}\] \[\Rightarrow \] \[{{C}_{0}}=\frac{C}{K}=\frac{C}{2}(K=2)\]