L}^{-3}}],\ [a]=[L]\] and \[[T]=[M{{T}^{-2}}]\] Comparing both sides, we get\[a=\frac{1}{2},\,b=\frac{3}{2}\] and \[c=\frac{-1}{2}\] \ \[\eta =\frac{k{{\rho }^{1/2}}{{a}^{3/2}}}{\SQRT{T}}\]

"> L}^{-3}}],\ [a]=[L]\] and \[[T]=[M{{T}^{-2}}]\] Comparing both sides, we get\[a=\frac{1}{2},\,b=\frac{3}{2}\] and \[c=\frac{-1}{2}\] \ \[\eta =\frac{k{{\rho }^{1/2}}{{a}^{3/2}}}{\SQRT{T}}\]

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Frequency is the function of density \[(\rho )\], length \[(a)\] and surface tension \[(T)\]. Then its value is?             [BHU 2003]            

NEET Physics in NEET 1 year ago

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Let \[n=k{{\rho }^{a}}{{a}^{b}}{{T}^{c}}\] where \[[\rho ]=[M{{L}^{-3}}],\ [a]=[L]\] and \[[T]=[M{{T}^{-2}}]\] Comparing both sides, we get\[a=\frac{1}{2},\,b=\frac{3}{2}\] and \[c=\frac{-1}{2}\] \ \[\eta =\frac{k{{\rho }^{1/2}}{{a}^{3/2}}}{\SQRT{T}}\]

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