L}^{B}}{{T}^{c}}\]             Substituting the DIMENSION of             \[[F]=[ML{{T}^{-2}}],\] \[[C]=[L]\ and\ [T]=[T]\]             and comparing both sides, we get \[m=F{{L}^{-1}}{{T}^{-2}}\]

"> L}^{B}}{{T}^{c}}\]             Substituting the DIMENSION of             \[[F]=[ML{{T}^{-2}}],\] \[[C]=[L]\ and\ [T]=[T]\]             and comparing both sides, we get \[m=F{{L}^{-1}}{{T}^{-2}}\]

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If force (F), length (L) and time (T) are assumed to be fundamental units, then the dimensional formula of the mass will be?                                                                                    [J & K CET 2004]

NEET Physics in NEET 1 year ago

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Let \[m=K{{F}^{a}}{{L}^{B}}{{T}^{c}}\]             Substituting the DIMENSION of             \[[F]=[ML{{T}^{-2}}],\] \[[C]=[L]\ and\ [T]=[T]\]             and comparing both sides, we get \[m=F{{L}^{-1}}{{T}^{-2}}\]

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