F=\FRAC{G{{m}_{1}}{{m}_{2}}}{{{d}^{2}}}\RIGHTARROW G=\frac{F{{d}^{2}}}{{{m}_{1}}{{m}_{2}}}\]                         \[1\,ly=9.46\times {{10}^{15}}\,meter\] \[[G]=\frac{[ML{{T}^{-2}}][{{L}^{2}}]}{[{{M}^{2}}]}=[{{M}^{-1}}{{L}^{3}}{{T}^{-2}}]\]

"> F=\FRAC{G{{m}_{1}}{{m}_{2}}}{{{d}^{2}}}\RIGHTARROW G=\frac{F{{d}^{2}}}{{{m}_{1}}{{m}_{2}}}\]                         \[1\,ly=9.46\times {{10}^{15}}\,meter\] \[[G]=\frac{[ML{{T}^{-2}}][{{L}^{2}}]}{[{{M}^{2}}]}=[{{M}^{-1}}{{L}^{3}}{{T}^{-2}}]\]

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The dimensions of universal gravitational constant are               [MP PMT 1984, 87, 97, 2000;  CBSE PMT 1988, 92; 2004   [MP PET 1984, 96, 99; MNR 1992; DPMT 1984; CPMT 1978, 84, 89, 90, 92, 96; AFMC 1999; NCERT 1975; DPET 1993; AIIMS 2000; RPET 2001; Pb. PMT 2002, 03; UPSEAT 1999; BCECE 2003, 05;]         

NEET Physics in NEET 1 year ago

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\[F=\FRAC{G{{m}_{1}}{{m}_{2}}}{{{d}^{2}}}\RIGHTARROW G=\frac{F{{d}^{2}}}{{{m}_{1}}{{m}_{2}}}\]                         \[1\,ly=9.46\times {{10}^{15}}\,meter\] \[[G]=\frac{[ML{{T}^{-2}}][{{L}^{2}}]}{[{{M}^{2}}]}=[{{M}^{-1}}{{L}^{3}}{{T}^{-2}}]\]

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Posted on 15 Aug 2024, this text provides information on NEET related to Physics in NEET. Please note that while accuracy is prioritized, the data presented might not be entirely correct or up-to-date. This information is offered for general knowledge and informational purposes only, and should not be considered as a substitute for professional advice.

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