THETA =\frac{{{F}_{e}}}{mg}\simeq \theta \] \[\frac{K{{q}^{2}}}{{{x}^{2}}mg}=\frac{x}{2\ell }\] or \[\] ..(1) or \[{{x}^{3/2}}\propto q\] ..(2) DIFFERENTIATE EQ.(i) w. r .t. TIME \[3{{x}^{2}}\frac{dx}{dt}\propto 2q\frac{dq}{dt}\] but \[\frac{dq}{dt}\] is constant so \[{{x}^{2}}(v)\propto q\]replace q from eq. (2) \[{{x}^{2}}(v)\propto {{x}^{3/2}}\] or \[\]