R}^{2}}}\] \[F'=\frac{K\frac{3Q}{4}\times \frac{3Q}{4}}{{{r}^{2}}}=\frac{9F}{16}\]

"> R}^{2}}}\] \[F'=\frac{K\frac{3Q}{4}\times \frac{3Q}{4}}{{{r}^{2}}}=\frac{9F}{16}\]

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Two point charges A and B, having charges +Q and Q respectively, are placed at certain distance apart and force acting between them is F. If 25 % charge of A is transferred to B, then force between the charges becomes- [NEET 2019]

NEET Physics in NEET 11 months ago

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[d] \[F=\frac{KQQ}{{{R}^{2}}}\] \[F'=\frac{K\frac{3Q}{4}\times \frac{3Q}{4}}{{{r}^{2}}}=\frac{9F}{16}\]

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Posted on 14 Aug 2024, this text provides information on NEET related to Physics in NEET. Please note that while accuracy is prioritized, the data presented might not be entirely correct or up-to-date. This information is offered for general knowledge and informational purposes only, and should not be considered as a substitute for professional advice.

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