F(0) = -1f(1) = 0.459697694Therefore, root lies between 0 and 1A = 0; f(a) = -1b = 1; f(b) = 0.459697694Substituting the values in the formula,X = \(\frac{bf(a)-af(b)}{f(a)-f(b)}\),we get \(x1 = \frac{-1}{-1-0.459697694}\)=0.685073357; f(x1) = -0.089299276Therefore, x1 becomes a to find the next point.\(X2 =\frac{-0.089299276-0.685073357(0.459697694)}{-0.089299276-0.459697694} \)= 0.736298997; f(x2) = -4.66039555*10-3Therefore, x2 becomes a to find the next point.\(X3 = \frac{-(-4.66039555*10^{-3})-0.736298997(0.459697694)}{(-4.66039555*10^{-3})-0.459697694}\)=0.738945355; f(x3) = -2.339261948*10-4Therefore, x3 becomes a to find the next point.\(X4 = \frac{(-2.339261948*10^{-4})-0.738945355(0.459697694)}{(-2.339261948*10^{-4})-0.459697694}\)=0.73907813; f(x4) = -1.172028721*10-5Therefore, x4 becomes a to find the next point.\(X5 = \frac{-(1.172028721*10^{-5})-0.73907813(0.459697694)}{(-1.172028721*10^{-5} )-0.459697694}\)=0.739084782Therefore, the positive root CORRECTED to 4 decimal places is 0.73908. "> F(0) = -1f(1) = 0.459697694Therefore, root lies between 0 and 1A = 0; f(a) = -1b = 1; f(b) = 0.459697694Substituting the values in the formula,X = \(\frac{bf(a)-af(b)}{f(a)-f(b)}\),we get \(x1 = \frac{-1}{-1-0.459697694}\)=0.685073357; f(x1) = -0.089299276Therefore, x1 becomes a to find the next point.\(X2 =\frac{-0.089299276-0.685073357(0.459697694)}{-0.089299276-0.459697694} \)= 0.736298997; f(x2) = -4.66039555*10-3Therefore, x2 becomes a to find the next point.\(X3 = \frac{-(-4.66039555*10^{-3})-0.736298997(0.459697694)}{(-4.66039555*10^{-3})-0.459697694}\)=0.738945355; f(x3) = -2.339261948*10-4Therefore, x3 becomes a to find the next point.\(X4 = \frac{(-2.339261948*10^{-4})-0.738945355(0.459697694)}{(-2.339261948*10^{-4})-0.459697694}\)=0.73907813; f(x4) = -1.172028721*10-5Therefore, x4 becomes a to find the next point.\(X5 = \frac{-(1.172028721*10^{-5})-0.73907813(0.459697694)}{(-1.172028721*10^{-5} )-0.459697694}\)=0.739084782Therefore, the positive root CORRECTED to 4 decimal places is 0.73908. ">

Find the positive root of the equation x-cosx using Regula Falsi method and correct to 4 decimal places.

Numerical Analysis Regula Falsi Method in Numerical Analysis 10 months ago

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F(0) = -1f(1) = 0.459697694Therefore, root lies between 0 and 1A = 0; f(a) = -1b = 1; f(b) = 0.459697694Substituting the values in the formula,X = \(\frac{bf(a)-af(b)}{f(a)-f(b)}\),we get \(x1 = \frac{-1}{-1-0.459697694}\)=0.685073357; f(x1) = -0.089299276Therefore, x1 becomes a to find the next point.\(X2 =\frac{-0.089299276-0.685073357(0.459697694)}{-0.089299276-0.459697694} \)= 0.736298997; f(x2) = -4.66039555*10-3Therefore, x2 becomes a to find the next point.\(X3 = \frac{-(-4.66039555*10^{-3})-0.736298997(0.459697694)}{(-4.66039555*10^{-3})-0.459697694}\)=0.738945355; f(x3) = -2.339261948*10-4Therefore, x3 becomes a to find the next point.\(X4 = \frac{(-2.339261948*10^{-4})-0.738945355(0.459697694)}{(-2.339261948*10^{-4})-0.459697694}\)=0.73907813; f(x4) = -1.172028721*10-5Therefore, x4 becomes a to find the next point.\(X5 = \frac{-(1.172028721*10^{-5})-0.73907813(0.459697694)}{(-1.172028721*10^{-5} )-0.459697694}\)=0.739084782Therefore, the positive root CORRECTED to 4 decimal places is 0.73908.

Posted on 29 Nov 2024, this text provides information on Numerical Analysis related to Regula Falsi Method in Numerical Analysis. Please note that while accuracy is prioritized, the data presented might not be entirely correct or up-to-date. This information is offered for general knowledge and informational purposes only, and should not be considered as a substitute for professional advice.

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