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Login12. A concave lens has a focal length of 10 cm. An object 2.5 cm high is placed 30 cm from the lens. Determine the position and size of the image. (3)
Physics Secondary School in Physics 9 months ago
Size and the position of the image is 0.625 and -7.5 cm respectively.
Given-
Focal length of the concave lens is NEGATIVE so f = -10 cm
Object distance from the lens is u = -30 cm
As, we know that
1/f = 1/v - 1/u where f is the focal length, v is the image distance from the lens and u is the object distance from the lens.
By putting the values in the above formula we get -
v = - 7.5 cm
And we know that magnification is EQUALS to HEIGHT of the image to the height of the object.
So, m = v/u = H1/H0
By putting the values we get -
H1/2.5 = -7.5/ -30
H1= 0.625
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Posted on 08 Nov 2024, this text provides information on Physics related to Secondary School in Physics. Please note that while accuracy is prioritized, the data presented might not be entirely correct or up-to-date. This information is offered for general knowledge and informational purposes only, and should not be considered as a substitute for professional advice.
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