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LoginCalculate the energy dissipated in kWh and J for a bulb of 250W. Which is used for 6 h
Physics Secondary School in Physics 1 year ago
-Power of the bulb = 250 WTime required = 6 hoursTo FIND :-The energy dissipated in kWh.The energy dissipated in J.Solution :-We know that,E = Energyp = Powert = TimeUsing the FORMULA,GIVEN that,Power (P) = 250 WTime (t) = 6 hours = 21600 secSubstituting their values,⇒ 250 = E/21600⇒ E = P × T⇒ E = 250 × 21600⇒ E = 5400000 J = 5.4 × 10⁶ JTherefore, the energy dissipated is 5.4 × 10⁶ J.
Posted on 26 Jul 2024, this text provides information on Physics related to Secondary School in Physics. Please note that while accuracy is prioritized, the data presented might not be entirely correct or up-to-date. This information is offered for general knowledge and informational purposes only, and should not be considered as a substitute for professional advice.
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