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LoginQuestion 5.12: A short bar magnet has a magnetic moment of 0.48 J T −1 . Give the direction and magnitude of the magnetic field produced by the magnet at a distance of 10 cm from the centre of the magnet on (a) the axis, (b) the equatorial lines (normal bisector) of the magnet.Class 12 - Physics - Magnetism And Matter Magnetism And Matter Page-201
Physics Secondary School in Physics 10 months ago
Given, Magnetic moment, M = 0.48J/T
distance of observation POINT from centre of the magnet, R = 10cm = 0.1m
(a) we know, magnetic field on AXIAL LINE due to magnetic dipole is given by ,
= (10^-7 × 2 × 0.48)/(0.1)³ = 9.6 × 10^-5T ALONG S-N direction.
(b) magnetic field on equatorial line due to magnetic dipole is given by ,
= (10^-7 × 0.48)/(0.1)³ = 4.8 × 10^-5 T along N-S direction.
Posted on 27 Nov 2024, this text provides information on Physics related to Secondary School in Physics. Please note that while accuracy is prioritized, the data presented might not be entirely correct or up-to-date. This information is offered for general knowledge and informational purposes only, and should not be considered as a substitute for professional advice.
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