Please allow ads on our site
Please log in to access this content. You will be redirected to the login page shortly.
LoginThe coefficient of static friction us between block A of mass 2 kg and the table .What would be the maximum mass value of block B so that the two blocks do not move ?The string and the pulley are assumed to be smooth and massless ( g = 10 m/s²)
Physics Secondary School in Physics 1 year ago
tion:The mass of the block A is 2kg, the coefficient of friction is 0.2.As the blocks do not MOVE THEREFORE, the tension in the string must be equal to the FORCE of friction on block A. Applying Newton's second law for block A,T=μ s m A g=0.2×2×10=4NApplying Newton's second law for block B,T=m B g4=m B ×10m B =0.4kgThus, the maximum mass of the block B is 0.4kg.Mark as brainlliest pls plspls
Posted on 09 Jul 2024, this text provides information on Physics related to Secondary School in Physics. Please note that while accuracy is prioritized, the data presented might not be entirely correct or up-to-date. This information is offered for general knowledge and informational purposes only, and should not be considered as a substitute for professional advice.
Take Quiz To Earn Credits!
Turn Your Knowledge into Earnings.
Answers
No matter what stage you're at in your education or career, TuteeHub will help you reach the next level that you're aiming for. Simply,Choose a subject/topic and get started in self-paced practice sessions to improve your knowledge and scores.
