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LoginWhat will be the time taken by electron to move with drift velocity from one end to the other end of copper conductor 3 metre long and carrying a current of 3 A ? [The cross-sectional area of the conductor = 2 x 10⁻⁶ m² and electron density for copper n = 8.5 X 10²⁸ m⁻³] (A) 2.72 x 10³s (B) 2.72 x 10⁴s (C) 2.72s (D) 2.72 x 10⁻⁴s
Physics Secondary School in Physics 10 months ago
udent,◆ Answer - (B)t = 2.72×10^4 s● Explaination -CURRENT flowing through conductor is given by -I = n.A.e.vv = I / n.A.ev = 3 / (8.5×10^28 × 2×10^-6 × 1.6×10^-19)v = 1.103×10^-4 m/sTime taken for e- to move with this drift velocity is -t = l / vt = 3 / 1.103×10^-4t = 2.72×10^4 sTherefore, 2.72×10^4 s will be taken for ELECTRON to move from one end to another.Hope this HELPS you...
Posted on 26 Sep 2024, this text provides information on Physics related to Secondary School in Physics. Please note that while accuracy is prioritized, the data presented might not be entirely correct or up-to-date. This information is offered for general knowledge and informational purposes only, and should not be considered as a substitute for professional advice.
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