TIME. Range = distance x Time TAKEN for the motion. The time can be found by utilising the fact that the vertical velocity becomes zero at the maximum HEIGHT (i.e. at HALF of the time period) and using the first equation of motion for this. Hence, on calculating, the range will be obtained as R = v2 (SIN 2θ)/g.

"> TIME. Range = distance x Time TAKEN for the motion. The time can be found by utilising the fact that the vertical velocity becomes zero at the maximum HEIGHT (i.e. at HALF of the time period) and using the first equation of motion for this. Hence, on calculating, the range will be obtained as R = v2 (SIN 2θ)/g.

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A body of mass m, projected at an angle of θ from the ground with an initial velocity of v, acceleration due to gravity is g, what is the maximum horizontal range covered?

Physics Simple Projectile Motion in Physics . 5 months ago

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The calculation for range uses the horizontal component of the initial velocity and TIME. Range = distance x Time TAKEN for the motion. The time can be found by utilising the fact that the vertical velocity becomes zero at the maximum HEIGHT (i.e. at HALF of the time period) and using the first equation of motion for this. Hence, on calculating, the range will be obtained as R = v2 (SIN 2θ)/g.

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Posted on 20 Dec 2024, this text provides information on Physics related to Simple Projectile Motion in Physics. Please note that while accuracy is prioritized, the data presented might not be entirely correct or up-to-date. This information is offered for general knowledge and informational purposes only, and should not be considered as a substitute for professional advice.

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