VALUE of coal = 26 MJ/kg⇒ Mass flow rate of fuel supplied = 43.75/26 = 1.6827 kg/s;GIVEN coal has sulphur content of 3.6 %⇒ Mass flow rate of sulphur = 1.6827 × 0.036 = 0.0605 kg/s;Moles of sulphur = 0.0605/32 = 1.89 × 10-3 kmol/s;A particular limestone to be FED to it at a calcium-sulphur molar ratio of 3.0Moles of calcium (CaCO3) required = 3 × 1.89 × 10-3 kmol/s = 5.679 × 10-3 kmol/s;Mass of CaCO3 required = 0.5679 kg/s;Mass of limestone required = 0.5679/0.85 = 0.668 kg/s = 2405 kg/hr;