EXPLANATION:Let σc and σT are the Compressive and tensile STRESSES developed in concrete at top and bottom fibre respectively due to given load ‘P’Since, stress DISTRIBUTION is Linear\(\frac{{{σ _c}}}{{50}} = \frac{{{σ _T}}}{{100}}\)⇒ \({σ _c} = \frac{{{σ _T}}}{2}\) ---(1)Case 1:Let an increasing the load, P (gradually), stresses in extreme, compression fibre reaches to its maximum permissible but in extreme TENSION fibres do not.i.e.σC = 15 MPa (given) and σt < 25 MPaNow,Using above equation (1)15 = σT/2 ⇒ σT = 30 MPa > 25 MPaHence, our assumption is wrong. Case 2:Now, assume that stress in external bottom fibre tensile stress reduce and maximum permissible value but in extreme top fibre do noti.e. σT = 25 MPa, σc ≤ 15 MPaNow, from equation (1)σC = 25/2 = 12.5 MPa < 15 MPa, Hence.⇒ compressive stress in extreme top fibre is 12.5 MPa which is less then its permissible value, when, extreme bottom fibre reaches to its maximum value. Therefore, it can be concluded that failure of section will be due to stresses in extreme fibre reaching to maximum permissible tensile stresses, on increasing the load gradually. "> EXPLANATION:Let σc and σT are the Compressive and tensile STRESSES developed in concrete at top and bottom fibre respectively due to given load ‘P’Since, stress DISTRIBUTION is Linear\(\frac{{{σ _c}}}{{50}} = \frac{{{σ _T}}}{{100}}\)⇒ \({σ _c} = \frac{{{σ _T}}}{2}\) ---(1)Case 1:Let an increasing the load, P (gradually), stresses in extreme, compression fibre reaches to its maximum permissible but in extreme TENSION fibres do not.i.e.σC = 15 MPa (given) and σt < 25 MPaNow,Using above equation (1)15 = σT/2 ⇒ σT = 30 MPa > 25 MPaHence, our assumption is wrong. Case 2:Now, assume that stress in external bottom fibre tensile stress reduce and maximum permissible value but in extreme top fibre do noti.e. σT = 25 MPa, σc ≤ 15 MPaNow, from equation (1)σC = 25/2 = 12.5 MPa < 15 MPa, Hence.⇒ compressive stress in extreme top fibre is 12.5 MPa which is less then its permissible value, when, extreme bottom fibre reaches to its maximum value. Therefore, it can be concluded that failure of section will be due to stresses in extreme fibre reaching to maximum permissible tensile stresses, on increasing the load gradually. ">

A simply supported beam of overall depth 150 mm has neutral axis at 50 mm from extreme top fibre. Permissible flexural stresses in extreme compression and extreme tension fibre are restricted to 15 MPa and 25 MPa respectively. If the load on the beam is increased gradually, then:

Prestressed Concrete Structures Beams And Slabs in Prestressed Concrete Structures 8 months ago

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EXPLANATION:Let σc and σT are the Compressive and tensile STRESSES developed in concrete at top and bottom fibre respectively due to given load ‘P’Since, stress DISTRIBUTION is Linear\(\frac{{{σ _c}}}{{50}} = \frac{{{σ _T}}}{{100}}\)⇒ \({σ _c} = \frac{{{σ _T}}}{2}\) ---(1)Case 1:Let an increasing the load, P (gradually), stresses in extreme, compression fibre reaches to its maximum permissible but in extreme TENSION fibres do not.i.e.σC = 15 MPa (given) and σt < 25 MPaNow,Using above equation (1)15 = σT/2 ⇒ σT = 30 MPa > 25 MPaHence, our assumption is wrong. Case 2:Now, assume that stress in external bottom fibre tensile stress reduce and maximum permissible value but in extreme top fibre do noti.e. σT = 25 MPa, σc ≤ 15 MPaNow, from equation (1)σC = 25/2 = 12.5 MPa < 15 MPa, Hence.⇒ compressive stress in extreme top fibre is 12.5 MPa which is less then its permissible value, when, extreme bottom fibre reaches to its maximum value. Therefore, it can be concluded that failure of section will be due to stresses in extreme fibre reaching to maximum permissible tensile stresses, on increasing the load gradually.

Posted on 04 Nov 2024, this text provides information on Prestressed Concrete Structures related to Beams And Slabs in Prestressed Concrete Structures. Please note that while accuracy is prioritized, the data presented might not be entirely correct or up-to-date. This information is offered for general knowledge and informational purposes only, and should not be considered as a substitute for professional advice.

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