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Login\eqalign{ & \frac{1}{2}\left( {\log x + \log y} \right)\,\,{\text{will}}\,{\text{equal}}\,{\text{to}} \cr & \log \left( {\frac{{x + y}}{2}} \right)\,\,{\text{if - }} \cr} $$
Question Bank Arithmetic Ability 1 year ago
Option 1 : y = 0
Option 2 : x = ‚à öy
Option 3 : x = y
Option 4 : x = y/2
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Best Answer
1 year ago
x = y/2Click Here For More